【メイク10】1,3,3,9を10にする方法





1,3,3,9と四則演算(+−×÷)を使用して10にする方法を紹介します。これはMake10、切符パズルなどと言います。

(ただし1と2を合せて12のような使い方は出来ません。)

61個の解法が見つかりました。


((1×9)+(3÷3))=10

((1+(3+9))-3)=10

((1+3)+(9-3))=10

((1+3)-(3-9))=10

((1+9)×(3÷3))=10

((1+9)+(3-3))=10

((1+9)-(3-3))=10

((1+9)÷(3÷3))=10

((1-3)+(3+9))=10

((3×(1+9))÷3)=10

((3+(1+9))-3)=10

((3+9)+(1-3))=10

((3+9)-(3-1))=10

((3-3)+(1+9))=10

((3÷3)×(1+9))=10

((3÷3)+(1×9))=10

((3÷3)+(9÷1))=10

((9+(1+3))-3)=10

((9+(3÷3))÷1)=10

((9-3)+(1+3))=10

((9÷1)+(3÷3))=10

(1×(9+(3÷3)))=10

(1+((3×9)÷3))=10

(1+((3+9)-3))=10

(1+(3×(9÷3)))=10

(1+(3+(9-3)))=10

(1+(3-(3-9)))=10

(1+(3÷(3÷9)))=10

(1+(9×(3÷3)))=10

(1+(9+(3-3)))=10

(1+(9-(3-3)))=10

(1+(9÷(3÷3)))=10

(1-((3-3)-9))=10

(1-((3-9)-3))=10

(1-(3-(3+9)))=10

(3×((1+9)÷3))=10

(3+((1+9)-3))=10

(3+(1+(9-3)))=10

(3+(1-(3-9)))=10

(3+(9+(1-3)))=10

(3+(9-(3-1)))=10

(3-((3-1)-9))=10

(3-((3-9)-1))=10

(3-(3-(1+9)))=10

(3÷(3÷(1+9)))=10

(9+((1×3)÷3))=10

(9+((1+3)-3))=10

(9+((3÷1)÷3))=10

(9+((3÷3)÷1))=10

(9+(1×(3÷3)))=10

(9+(1+(3-3)))=10

(9+(1-(3-3)))=10

(9+(1÷(3÷3)))=10

(9+(3×(1÷3)))=10

(9+(3+(1-3)))=10

(9+(3-(3-1)))=10

(9+(3÷(1×3)))=10

(9+(3÷(3÷1)))=10

(9-((3-1)-3))=10

(9-((3-3)-1))=10

(9-(3-(1+3)))=10



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