（ただし１と２を合せて１２のような使い方は出来ません。）
53個の解法が見つかりました。
(((2×7)÷1)-4)=10
((1×(2×7))-4)=10
((1+(4+7))-2)=10
((1+4)+(7-2))=10
((1+4)-(2-7))=10
((1+7)+(4-2))=10
((1+7)+(4÷2))=10
((1+7)-(2-4))=10
((1-2)+(4+7))=10
((2×(1×7))-4)=10
((2×(7÷1))-4)=10
((2×7)-(1×4))=10
((2×7)-(4÷1))=10
((2÷(1÷7))-4)=10
((4+(1+7))-2)=10
((4+7)+(1-2))=10
((4+7)-(2-1))=10
((4-2)+(1+7))=10
((4÷2)+(1+7))=10
((7×(1×2))-4)=10
((7×(2÷1))-4)=10
((7+(1+4))-2)=10
((7-2)+(1+4))=10
((7÷(1÷2))-4)=10
(1×((2×7)-4))=10
(1+((4+7)-2))=10
(1+(4+(7-2)))=10
(1+(4-(2-7)))=10
(1+(7+(4-2)))=10
(1+(7+(4÷2)))=10
(1+(7-(2-4)))=10
(1-((2-4)-7))=10
(1-((2-7)-4))=10
(1-(2-(4+7)))=10
(4×((7÷2)-1))=10
(4+((1+7)-2))=10
(4+(1+(7-2)))=10
(4+(1-(2-7)))=10
(4+(7+(1-2)))=10
(4+(7-(2-1)))=10
(4-((2-1)-7))=10
(4-((2-7)-1))=10
(4-(2-(1+7)))=10
(7+((1+4)-2))=10
(7+(1+(4-2)))=10
(7+(1+(4÷2)))=10
(7+(1-(2-4)))=10
(7+(4+(1-2)))=10
(7+(4-(2-1)))=10
(7-((2-1)-4))=10
(7-((2-4)-1))=10
(7-(2-(1+4)))=10