（ただし１と２を合せて１２のような使い方は出来ません。）
61個の解法が見つかりました。
(((5+7)÷1)-2)=10
((1×(5+7))-2)=10
((1×5)+(7-2))=10
((1×5)-(2-7))=10
((1×7)+(5-2))=10
((1×7)-(2-5))=10
((1+(2×7))-5)=10
((1-5)+(2×7))=10
((2×7)+(1-5))=10
((2×7)-(5-1))=10
((5+(1×7))-2)=10
((5+(7-2))÷1)=10
((5+(7÷1))-2)=10
((5+7)-(1×2))=10
((5+7)-(2÷1))=10
((5-(2-7))÷1)=10
((5-2)+(1×7))=10
((5-2)+(7÷1))=10
((5÷1)+(7-2))=10
((5÷1)-(2-7))=10
((7+(1×5))-2)=10
((7+(5-2))÷1)=10
((7+(5÷1))-2)=10
((7-(2-5))÷1)=10
((7-2)+(1×5))=10
((7-2)+(5÷1))=10
((7÷1)+(5-2))=10
((7÷1)-(2-5))=10
(1×((5+7)-2))=10
(1×(5+(7-2)))=10
(1×(5-(2-7)))=10
(1×(7+(5-2)))=10
(1×(7-(2-5)))=10
(1+((2×7)-5))=10
(1-(5-(2×7)))=10
(5+((1×7)-2))=10
(5+((7-2)÷1))=10
(5+((7÷1)-2))=10
(5+(1×(7-2)))=10
(5+(7-(1×2)))=10
(5+(7-(2÷1)))=10
(5-((1×2)-7))=10
(5-((2-7)÷1))=10
(5-((2÷1)-7))=10
(5-(1×(2-7)))=10
(5-(2-(1×7)))=10
(5-(2-(7÷1)))=10
(7+((1×5)-2))=10
(7+((1+5)÷2))=10
(7+((5-2)÷1))=10
(7+((5÷1)-2))=10
(7+(1×(5-2)))=10
(7+(5-(1×2)))=10
(7+(5-(2÷1)))=10
(7-((1×2)-5))=10
(7-((2-5)÷1))=10
(7-((2÷1)-5))=10
(7-(1×(2-5)))=10
(7-(2-(1×5)))=10
(7-(2-(5÷1)))=10